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1.1.A solution of rubbing alcohol is 70.3 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 94.3 mL sample of the rubbing alcohol solution? 2.How many liters of a 3.28 M K2SO4 solution are needed to provide 80.5 g of K2SO4 (molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Write the net ionic equation 3.Na2SO4(aq) and BaCl2(aq). How many milliliters of isopropanol are in a 94.3 mL sample of the rubbing alcohol solution? 2.How many liters of a 3.28 M K2SO4 solution are needed to provide 80.5 g of K2SO4 (molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Write the net ionic equation 3.Na2SO4(aq) and BaCl2(aq)

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1.A solution of rubbing alcohol is 70.3 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a

94.3 mL sample of the rubbing alcohol solution?

2.How many liters of a 3.28 M K2SO4 solution are needed to provide 80.5 g of K2SO4 (molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L.

Write the net ionic equation

3.Na2SO4(aq) and BaCl2(aq)

 
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