100.0 mL of 0.40 M HNO, is titrated with a 0.20 M KOH solution. a) What volume of titrant is required to reach the equivalence point? KUH + HNO 3 > KNO3 + HZO
1. 100.0 mL of 0.40 M HNO, is titrated with a 0.20 M KOH solution.
a) What volume of titrant is required to reach the equivalence point?
KUH + HNO 3 > KNO3 + HZO
moles of KOHcall
mava = mbvb
0.020, 10 0 L
( 10 0.0 ML ) ( 0. 4 0 m) = ( 0.20 m ) Vb
0. 20 m
0. 20 m
Vb = 200 ml
b) What is the initial pH for this titration?
KOH + HNU 3 – KNU3 + H20
6. 40 m 0. 40m
KNO 3 = 0- 40 m
-0.40m – 0. 40 m
+ 0.40 m
O .
0. 40
c) Write the neutralization reaction between HNO3 and KOH.
H + + OH – – HZO