Entries by Hannah Wangui

Question Question Compound ΔH°f (kJ/mol) H2O (g) -241.9 CO2 (g) -393.5 The combustion of 2,3,4-trimethylpentane to CO2 (g) and H2O (g) produces -5069 kJ/mol of energy. What is ΔH°f of 2,3,4-trimethylpentane? Top Answer. What is ΔH°f of 2,3,4-trimethylpentane? Top Answer

August 20, 2019 in /by

Question Compound ΔH°f (kJ/mol)H2O (g) -241.9CO2 (g) -393.5The combustion of 2,3,4-trimethylpentane to CO2 (g) and H2O (g) produces -5069 kJ/mol of energy. What is ΔH°f of 2,3,4-trimethylpentane? Top Answer   Looking for a Similar Assignment? Order now and Get 10% Discount! Use Coupon Code “Newclient”

 

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Use the following data to answer this question. Compound ΔH°f (kJ/mol) H2O (g) -241.9 CO2 (g) -393.5 HCl (g) -92.3 O3 (g) +142.3 O (g) +247.5 What is the enthalpy change for the overall process composed of two steps shown below? (Cl is chlorine, not carbon and iodine.) ClO(g) + O3(g) → ClO2(g) + O2(g) ClO2(g) + O(g) → ClO(g) + O2(g)Compound ΔH°f (kJ/mol) H2O (g) -241.9 CO2 (g) -393.5 HCl (g) -92.3 O3 (g) +142.3 O (g) +247.5 What is the enthalpy change for the overall process composed of two steps shown below? (Cl is chlorine, not carbon and iodine.) ClO(g) + O3(g) → ClO2(g) + O2(g) ClO2(g) + O(g) → ClO(g) + O2(g)

August 20, 2019 in /by

Use the following data to answer this question.Compound ΔH°f (kJ/mol)H2O (g) -241.9CO2 (g) -393.5 HCl (g) -92.3 O3 (g) +142.3 O (g) +247.5 What is the enthalpy change for the overall process composed of two steps shown below? (Cl is chlorine, not carbon and iodine.) ClO(g) + O3(g) → ClO2(g) + O2(g) ClO2(g) + O(g) […]

 

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Question Question If an inflatable device has a volume of 1.57 x 106 L. And in order to use enough O2 to inflate it we use this reaction: 2 KClO3 (s) → 3 O2 (g) + 2 KCl (s) If the temperature is 4.00 C and the pressure is 1.00 atm, how many grams of KClO3 (s) are required to produce 1.57 x 106 L of O2 (g)? R=0.08206 Lxatm/molxk Pv=nrt (1.00atm)(1.57×106 L)=(x)(0.08206 L*atm/mol*k)(277.15) 1.57×106 L = 22.742929(x) x=69032.44521 mol O2 69032.44521 mol O2 * 2 mol KClO3 / 3 mol O2 = 138064.8904 mol KClO3 138064.8904 mol KClO3 * 122.548 g / 1 mol KClO3 16919576.19 g KClO3 Trying to make sure my calculations are right. Thanks. And in order to use enough O2 to inflate it we use this reaction: 2 KClO3 (s) → 3 O2 (g) + 2 KCl (s) If the temperature is 4.00 C and the pressure is 1.00 atm, how many grams of KClO3 (s) are required to produce 1.57 x 106 L of O2 (g)? R=0.08206 Lxatm/molxk Pv=nrt (1.00atm)(1.57×106 L)=(x)(0.08206 L*atm/mol*k)(277.15) 1.57×106 L = 22.742929(x) x=69032.44521 mol O2 69032.44521 mol O2 * 2 mol KClO3 / 3 mol O2 = 138064.8904 mol KClO3 138064.8904 mol KClO3 * 122.548 g / 1 mol KClO3 16919576.19 g KClO3 Trying to make sure my calculations are right. Thanks

August 20, 2019 in /by

Question If an inflatable device has a volume of 1.57 x 106 L. And in order to use enough O2 to inflate it we use this reaction: 2 KClO3 (s) → 3 O2 (g) + 2 KCl (s) If the temperature is 4.00 C and the pressure is 1.00 atm, how many grams of KClO3 (s) are […]

 

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Question . Question . Calculate the osmolarity of these solutions. Assume density of the solution is 1.00 g/mL. /> (a) 3.80 M MgCl2 solution Osmolarity = (b) 4.40% w/w glucose (C6H12O6) solution Osmolarity = . Assume density of the solution is 1.00 g/mL. /> (a) 3.80 M MgCl2 solution Osmolarity = (b) 4.40% w/w glucose (C6H12O6) solution Osmolarity =

August 20, 2019 in /by

Question . Calculate the osmolarity of these solutions. Assume density of the solution is 1.00 g/mL. />           (a) 3.80 M MgCl2 solution                                        Osmolarity =           (b) 4.40% w/w glucose (C6H12O6) solution             Osmolarity =   Looking for a Similar Assignment? Order now and Get 10% Discount! Use Coupon Code “Newclient”

 

Looking for a Similar Assignment? Order now and Get 10% Discount! Use Coupon Code "Newclient"