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identity theft.

Question

select an article that details current methods that are used to successfully prevent identity theft. Discuss what

security policies commerce should implement to prevent it from happening. Also, address the options users can take to protect themselves.

 
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An electrochemical cell

Question

An electrochemical cell consists of a silver electrode in contact with 346 mL of 0.1 M AgNO3 solution and a

magnesium electrode in contact with 288 ml of a 0.1 M Mg(NO3)2 solution (a) calculate the value for E for the cell at 25oC (b) A current is drawn from the cell until 1.20 g of silver have been deposited at the silver electrode. Calculate the value of E for the cell at that stage of operation.

 
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Trial

Question

1.  Record the following for each of the three trials:
·  Trial

1

aMass of the empty calorimeter (g)18.6g
bInitial temperature of the calorimeter (°C)21.5°C
cMaximum temperature in the calorimeter from the reaction (°C)35.0°C
dCalculate ΔT by subtracting (b) from (c) (°C) ΔT = Tmaximum – Tinitial35.0°C-21.5°C=13.5°C
eMass of the calorimeter and its contents after the reaction (g)68.74g
fCalculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)68.74g-18.6g=50.14g
gCalculate the moles of Mg reacted (MW = 24.305 g/mole)?50mL of 1M HCI is 50/1000×1=0.05.15/24.305=.006g/mole

·  Trial 2

aMass of the empty calorimeter (g)18.6g
bInitial temperature of the calorimeter (°C)21.5°C
cMaximum temperature in the calorimeter from the reaction (°C)44.0°C
dCalculate ΔT by subtracting (b) from (c) (°C) ΔT = Tmaximum – Tinitial44.0°C-21.5°C=22.5°C
eMass of the calorimeter and its contents after the reaction (g)68.83g
fCalculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)68.83-18.6=50.23
gCalculate the moles of Mg reacted (MW = 24.305 g/mole).25/24.305=.010g/mole

·  Trial 3

aMass of the empty calorimeter (g)18.6g
bInitial temperature of the calorimeter (°C)21.5°C
cMaximum temperature in the calorimeter from the reaction (°C)52.9°C
dCalculate ΔT by subtracting (b) from (c) (°C) ΔT = Tmaximum – Tinitial52.9°C-21.5°C=31.4°C
eMass of the calorimeter and its contents after the reaction (g)68.92g
fCalculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)68.92g-18.6g=50.32
gCalculate the moles of Mg reacted (MW = 24.305 g/mole).35/24.305=.014g/mole

2.  Calculate the heat released into the solution for the 3 reactions, according to the formula:

qreaction= (Ccal * ΔT) + (mcontents* Cpcontents* ΔT)

3.  
Assume Cpcontents= Cpwater= 4.18 J/g °C

aTrial 1 (J)(4.18J/g°C)(68.74g)(35.0°C-21.5°C)=3878.9982 J/g°C
bTrial 2 (J)(4.18J/g°C)(68.83g)(44.0°C-21.5°C)=6473.4615 J/g°C
cTrial 3 (J)(4.18J/g°C)(68.92g)(52.9°C-21.5°C)=9045.88784 J/g°C

4.  Find the molar heat of reaction for each experiment in units of kilojoules / (mole of Mg) by dividing the heat of reaction (converted to kJ by dividing by 1000) by the moles of Mg used.

aTrial 1 (kJ/mol)
bTrial 2 (kJ/mol)
cTrial 3 (kJ/mol)

5.  Calculate and record the average molar heat of reaction from the three results:

 
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Business Data Communications

Question

Test bank questions and answers for test prep. Book is “Business Data Communications” 7th edition by Stallings

 
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