Consider the following collection of n = 9 closing prices
Question Consider the following collection of n = 9 closing prices for stock ABC: 101.02,102.23,100.34,99.87,98.65,96.45,98.45,99.00,100.05Compute the standard estimator of the volatility parameter σ using these closing prices.Using the estimate of σ above, what is an estimate of the drift parameter µ for the price paths of ABC assuming the paths of ABC can be modeled by a risk-neutral geometric Brownian motion. Assume the interest rate is 0. (Hint: in the risk-neutral setting, how is the drift parameter related to the volatility?)
Lupe put $ style=”color:rgb(0,0,0);”>12,000 in a certificate of deposit that
Question Lupe put $ style=”color:rgb(0,0,0);”>12,000 in a certificate of deposit that gained interest at a rate of 8.5%. How much interest did the account gain after 2 months?(Round to the nearest cent as needed)
Suppose researchers are interested in a program that is intended
Question Suppose researchers are interested in a program that is intended to reduce overall calorie intake in a group of women looking to lose weight after pregnancy. The program manager sets a daily calorie intake limit of 2,050calories/day. Which of the following represents the null and alternative hypotheses representing a two-sided one sample t-test for the average calorie consumption in the weight management program?
Use the future value formula to find the indicated value:n=
Question Use the future value formula to find the indicated value:n= 37; i = 0.02; PMT= $43; FV=?(Please round to the nearest cent)
A family has a $120,801, style=”color:rgb(0,0,0);”>15-year mortgage at 4.8 %
Question A family has a $120,801, style=”color:rgb(0,0,0);”>15-year mortgage at 4.8 % compounded monthly.(A) Find the monthly payment and the total interest paid.(B) Suppose the family decides to add an extra $100 to its mortgage payment each month starting with the very first payment. How long will it take the family to pay off the mortgage? How much interest will the family save?(A) Monthly Payment (Rounded to two decimal places) Total Interest paid (Rounded to two decimal places)(B) Time: In years (Rounded to two decimal places) Total interest saved (Rounded to two decimal places)
My question is for question 6 how to calculate the
Question My question is for question 6 how to calculate the “Adjusted MapQuest times” for the sample of 500 deliveries? 5. A driver reads your answer to part (4) and makes the following comment: MapQuest gives driving times for cars. Driving times for trucks will probably be longer because we can’t go as fast, especially in city traffic. Is there some way to adjust the MapQuest prediction to make it fit trucks better? Construct a fitted line plot (scatterplot with fitted linear regression line) using the MapQuest times as the predictor variable and the actual times as the response variable. Call the regression values ‘Adjusted MapQuest’ times. Provide the fitted line plot, regression equation and R2 values associated with the ‘Adjusted MapQuest’ times. Interpret your results and indicate whether the driver’s suggestion is valid or invalid. The plot is given below,From the above plot we can see that the regression equation is,Actual times = 9.3392 0.8788*MapQuestThe R2 value is 0.7937 implying very accurate model. Now the regression model adjusts for both the smaller and large values and hence the about regression model would be useful. There are lots of value below the regression line implying the drivers claim is correct as well. 6. Use the regression equation given in part (5) to provide ‘Adjusted MapQuest’ times for the sample of 500 deliveries and calculate the Adjusted Deviations = Actual times – Adjusted MapQuest times. (You do NOT need to put those values here.) Construct an appropriate graph for comparing the deviations associated with the Old Computer Model, the MapQuest model and Adjusted MapQuest model and include it here. Interpret the graph and recommend the modeling tool (method of predicting delivery times) you feel is most accurate. The histograms would be most appropriate. The obtained histograms are given below, In part (4) we observed that the deviations for Mapquest was better than the old model. Here we can see that the deviation for Adjusted Map Quest is even better. Though the range may be almost same for adjusted and unadjusted Map Quest deviations but as the number of values close to 0 is higher for Adjusted model so the standard deviation and variation is smaller for Adjusted Map Quest model deviations.Thus the most accurate model tool is the adjusted Map Quest model.
Introduction: This learning lab is very similar to last week’s
Question Introduction: This learning lab is very similar to last week’s learning lab. We will look at the same data but now analyze them as if they came from a study in which each individual completed every condition. After performing the analyses, you will compare the results to the results we obtained in the previous learning lab. The goal of this exercise is to give you a sense of the differences between independent sample and related sample designs.The data in Excel: Open the file ‘PSYCH200_Lesson_10_Learning_Lab.xls with Excel.You should see two datasets, which were obtained from the same set of individuals. Let’s again imagine that these data come from an experiment in which a researcher aimed to determine whether reading a chapter first and then going to a lecture is a better learning method than going to a lecture first and then reading the chapter.To address this question, the researcher recruited 25 people, and subjected each individual to the reading then lecture condition (condition 1) and to the lecture then reading condition (condition 2).The order of these conditions was randomized to make sure that any differences that could be found between these methods is not due to the fact that people had more practice for the second condition they performed. Again, the researcher assessed learning by having each participant complete a test on the material afterwards. In this case, two different sets of materials were used to avoid that people were tested on the same material twice. Column A of the Excel sheet displays the scores for condition 1, and column B displays the scores for condition 2.Step 1: Calculate the t-value for the data setBased on the two datasets, we will calculate the t-value in cell G13. For this, we use the paired sample t-test procedure. Here is the formula:t=MD−μDsMDt=MD−μDsMDLet’s break this down into smaller steps:Step 1a: MD and µDFirst, calculate the difference score for each individual by subtracting the score in condition 1 from the score in condition 2. Put the difference scores in cells C2 to C26. Calculate the mean difference score and put the result in cell H2.Usually, no difference is predicted between two conditions based on the null hypothesis H0. Thus, µD = 0. This is displayed in cell G4.Step 1b: sMDIn the next step, we need to calculate the standard error of the mean. For this, we use the following formula:sMD=sn√sMD=snLet’s break this down into its components. First, we need to calculate the variance s2 so we can calculate the standard deviation s. Here is the formula for calculating the variance s2:s2=SSn−1=SSdfs2=SSn−1=SSdfCalculate the sum of squares. You will do this the same way you calculated SS for t-scores (i.e., LL8 and LL9). First, subtract each difference scores from the mean difference score in column D. Then, square these values to get the squared deviations from the mean difference in column E. Sum these values and put the answer in cell H5.Put the degrees of freedom df in cell H6.Now we can calculate the variance. Do so in cell H7. Next, take the square root of the variance s2 to get the standard deviation s. Put the result in cell H8.s=s2−−√s=s2Finally, to get sMD, take the standard deviation s, and divide it by the square root of the number of difference scores n. Put the result in cell H9.sMD=sn√sMD=snStep 1c: T-valueCalculate the value for t based on the quantities you calculated in the previous steps. Again, use the following formula for t:t=MD−μDsMDt=MD−μDsMDSave your workStep 2: Determine the one-tailed and two-tailed probabilitiesAs we saw in the previous lesson, Excel has a build-in function to calculate probabilities with a t-test. This function is called =TTEST(). This function takes four input arguments; the data for the first condition (array 1), the data for the second condition (array 2), whether the test is one-tailed or two-tailed (nondirectional), and the type of test.One-tailed probability testWe will calculate the one-tailed probability for the paired sample t-test in cell H16.For array 1, you want to select the data for condition 1 (cells A2:A26. For array 2, you want to select the data for condition 2 (cells B2:B26).First, we will do a one-tailed (directional) test of the null hypothesis H0. To do so, put in the value 1 for Tails. For Type, put in the value 1. This corresponds to a paired sample t-test. Thus, the formula in cell H16 should say = TTEST(A2:A26,B2:B26,1,1). A probability should appear in cell H16 after you hit Enter.Two-tailed probability testNow, perform a two-tailed probability test on the data by adjusting the formula for the t-test and putting the answer in cell H17.Save your workStep 3: Making inferencesBased on the probabilities you found for the one-tailed and two-tailed t-test, answer questions Q1 and Q2 in cells I16 and I17. Put your Yes/No answer in cells J16 and J17.Save your workStep 4: Comparing the independent sample and paired sample t-testFinally, go back to the previous learning lab and review the results. Compare them to the results you got in this learning lab. You should find that even though the data were the same in the two cases, the result of the t-test is different.Answer question Q3 displayed in cells I19 and I20 by putting your Yes/No answer in cell J20 ATTACHMENT PREVIEW Download attachment Screenshot (2).png AutoSave . Off) PSYCH200_LL10_WILLIAMS – Compatibility Mode – Saved Tasha-Gaye Tracey X File Home Insert Page Layout Formulas Data Review View Help Search Share Comments AutoSum LO Calibri – 11 AA = ab Wrap Text General Fill AY O Paste BIU – a . A . Merge
The annual per capita consumption of bottled water was 32.7
Question The annual per capita consumption of bottled water was 32.7 gallons. Assume that the per capita consumption of bottled water is approximately normally distributed with a mean of 32.7 and a standard deviation of 10 gallons. The probability that someone consumed more than 38 gallons of bottled water is nothing .10 gallons.
Hi, I am trying to figure out how to fill
Question Hi, I am trying to figure out how to fill out a histogram on a word document for my homework and it never looks right. How do I fill in excel with the numbers from this question to create a histogram? Suppose you have an experiment where you flip a coin three times. You then count the number of heads.a.) State the random variable.X=Number of heads, H=heads, T=tailsb.) Write the probability distribution for the number of heads.X can equal 0,1,2, or 3. HHH TTTHTT TTHHHT THTHTH THHP (0)= P(TTT)=1/8 P (1)= P(HTT,TTH,THT)=3/8P (2)= P(HHT, HTH,THH) =3/8P (3)= P(HHH)= 1/8c.) Draw a histogram for the number of heads.
A 0.70 kg ball moving horizontally at 5.0 m/s strikes
Question A 0.70 kg ball moving horizontally at 5.0 m/s strikes a vertical wall and rebounds with speed 2.0 m/s. What is the magnitude of the change in its linear momentum?
Use the normal distribution of IQ scores, which has a
Question Use the normal distribution of IQ scores, which has a mean of 75 and a standard Deviation of 13, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. The percentage of scores between 49 and 94.5 is _______%. (Round to two decimal places as needed) ATTACHMENT PREVIEW Download attachment qa_attachment_1562547401182.jpg Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Full data set Standard score % Standard % score – 3.0 0.13 0. 1 53.98 – 2.5 0.62 0.5 69.15 – 2 2.28 0.9 81.59 – 1.5 6.68 1 84.13 – 1 15.87 1.5 93.32 – 0.9 18.41 2 97.72 0.5 30.85 2.5 99.38 – 0.1 46.02 3 99.87 0 50.00 3.5 99.98Read more
Eyeglassomatic manufactures eyeglasses for different retailers. They test to see
Question Eyeglassomatic manufactures eyeglasses for different retailers. They test to see how many defective lenses they made in a time period. Table #4.2.2 gives the defect and the number of defects.Table #4.2.2: Number of Defective Lenses Defect type Number of defects Scratch 5865 Right shaped – small 4613 Flaked 1992 Wrong axis 1838 Chamfer wrong 1596 Crazing, cracks 1546 Wrong shape 1485 Wrong PD 1398 Spots and bubbles 1371 Wrong height 1130 Right shape – big 1105 Lost in lab 976 Spots/bubble – intern 976 25,891a.) Find the probability of picking a lens that is scratched or flaked.0.31b.) Find the probability of picking a lens that is the wrong PD or was lost in lab.0.09c.) Find the probability of picking a lens that is not scratched.d.) Find the probability of picking a lens that is not the wrong shape.I’m not sure if i’m doing these problems correctly?
Use the normal distribution of IQ scores, which has a
Question Use the normal distribution of IQ scores, which has a mean of 100 and a standard Deviation of 11, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. The percentage of scores between 72.5 and 127.5 is _______%. (Round to two decimal places as needed) ATTACHMENT PREVIEW Download attachment qa_attachment_1562548504592.jpg Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Full data set Standard score % Standard % score – 3.0 0.13 0.1 53.98 – 2.5 0.62 0.5 69.15 – 2 2.28 0.9 81.59 – 1.5 6.68 1 84.13 – 1 15.87 1.5 93.32 – 0.9 18.41 2 97.72 – 0.5 30.85 2.5 99.38 – 0.1 46.02 3 99.87 0 50.00 3.5 99.98Read more
Use the normal distribution of heights of adult women, which
Question Use the normal distribution of heights of adult women, which has a mean of 165 centimeters and a standard Deviation of 7 centimeters and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. The percentage of heights greater than 158 centimeters is ______%. (Round to two decimal places as needed) ATTACHMENT PREVIEW Download attachment qa_attachment_1562549587625.jpg Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Full data set Standard score % Standard % score – 3.0 0.13 0.1 53.98 – 2.5 0.62 0.5 69. 15 – 2 2.28 0.9 81.59 – 1.5 6.68 84.13 – 1 15.87 1.5 93.32 – 0.9 18.41 2 97.72 0.5 30.85 2.5 99.38 – 0.1 46.02 3 99.87 0 50.00 3.5 99.98Read more
The normal distribution of heights of adult women has a
Question The normal distribution of heights of adult women has a mean of 161 centimeters and a standard Deviation of 5 centimeters, ive included a table with the standard scores and percentiles for a normal distribution.The percentage of heights less than 158.5 centimeters is ______%. Round to two decimal places as needed ATTACHMENT PREVIEW Download attachment qa_attachment_1562550140370.jpg Full data set Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Standard score % Standard % score – 3.0 0.13 0.1 53.98 – 2.5 0.62 0.5 69.15 – 2 2.28 0.9 81.59 – 1.5 6.68 1 84.13 – 1 15.87 1.5 93.32 – 0.9 18.41 2 97.72 – 0.5 30.85 2.5 99.38 – 0.1 46.02 3 99.87 0 50.00 3.5 99.98Read more
Is there a way to tell whether the mean or
Question Is there a way to tell whether the mean or median is greater without actually calculating it with the numbers? src=”/qa/attachment/8336465/” alt=” question1.PNG” /> Attachment 1 Attachment 2 ATTACHMENT PREVIEW Download attachment coursehero question1.PNG ATTACHMENT PREVIEW Download attachment courseheroquestion2.PNG
Please help me with the tasks below Thank you! src=”/qa/attachment/8336605/”
Question Please help me with the tasks below Thank you! src=”/qa/attachment/8336605/” alt=”temp2.PNG” /> Attachment 1 Attachment 2 Attachment 3 ATTACHMENT PREVIEW Download attachment temp1.PNG ATTACHMENT PREVIEW Download attachment temp2.PNG ATTACHMENT PREVIEW Download attachment temp3.PNG
- Provide A SWOT (Strengths, Weaknesses, Opportunities, and Threats) analysis of
Question
- Provide A SWOT (Strengths, Weaknesses, Opportunities, and Threats) analysis of the chaplain’s duties and responsibilities from AD 1200 – AD 1600
- Did the nature of the enemy make a difference during the wars of the Three Kingdoms (1642-1649)?
- Take a favorable position on personnel administration in churches, agreeing
Question
- Take a favorable position on personnel administration in churches, agreeing in a well thought out thread.
- Address the question: Does personnel administration apply to lay/volunteer personnel? Why or why not?
Jim and Sally are playing catch but neither of them
Question Jim and Sally are playing catch but neither of them is very good at catching the ball. When Jimthrows to Sally, 1/3 of the time she gets the ball, 1/6 of the time Jim retrieves it, 1/6 of the time thedog runs off with it, and 1/3 of the time it rolls down the storm sewer. When Sally throws to Jim, 1/3of the time he gets it, 1/3 of the time Sally retrieves it, 1/6 of the time the dog runs off with it, and1/6 of the time it rolls down the storm sewer. If Sally has the ball now, what is the probability theball ends up in the storm sewer
Suppose that at a certain bank that the probability that
Question Suppose that at a certain bank that the probability that someone who has overdrawn their account in the past will subsequently default on a new loan is 8%. The probability that someone who has not overdrawn their account will subsequently default is 0.6% (or 0.006). The probability that a customer will overdraw their account in general is 40%.Let O represent Overdrawing and D represent Defaulting. NO represent Not Overdrawing and ND represent Not DefaultingUse this notation for the remainder of the problem below.A. Write the three given probabilities using the symbol for conditional probability where necessary. Probability ( ) = ________ Probability ( | ) = ________Probability ( | ) = ________B. What is the probability of Default on a loan? Show all work. Mark your final answer. C. Of those who default on their loan, what is the proportion who had previously overdrawn their account? That is, what is Pr(O|D)? Show all work. Mark your final answer.
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