Describe The Steps Involved In Converting Glycerol Into Triacylglycerol. Explain The Roles Of

Describe the steps involved in converting glycerol into triacylglycerol. Explain the roles of the citrate shuttle with regards to the fat synthesis pathway by describing how acetyl groups are transported into the cytosol and the paths the products of the cytosolic cleavage reaction take. As in glycolysis and the degradation of glucose, the degradation of fatty acids also requires an initial investment of ATP energy. State the reaction or reactions where ATP energy is needed before fatty acids can be oxidized.

Viable Plate Count Using The Formula: Cfu/ml = (no. Of Colonies X Dilution Factor)

Viable plate count Using the formula: cfu/ml = (no. of colonies x dilution factor) / volume of culture plate In plate 10-4 there were 150 colonies counted. Experimental process: Pipet 0.25 mL of the S. cerevisiae solution into the test tube labeled 10-1. Pipet the solution up and down several times to ensure all organisms are rinsed from the pipet into the test tube. Pipet 0.25 mL of the 10-1 S. cerevisiae solution into the test tube labeled 10-2. Pipet the solution up and down several times to ensure all organisms are rinsed from the pipet into the test tube. Repeat the transfer process to pipet the S. cerevisiae solution from the 10-2 tube to the 10-3 tube; from the 10-3 tube to the 10-4 tube; from the 10-4 tube to the 10-5 tube; and from the 10-5 tube to the 10-6 tube. The yeast was added to 2.25ml of distilled water. The a pipet 0.125 mL (4 drops) of each solution was added to the corresponding plate. Calculate: – Dilution Plate CFUs – Dilution Factor of Viable Plate – Volume of Diluent added to Plate – CFU/mL of Original Sample: – CFU/(Volume x Dilution Factor)

It Took 2minutes16secondsfor The 2.5%pepsin To Clear The Albumen, And 3minutes And12 Seconds For

it took 2minutes16secondsfor the 2.5%pepsin to clear the albumen, and 3minutes and12 seconds for the 2% 1.5% pesin took 4minutes and 20seconds . 0.5 pepsin took 9.15 and 1% too 6.10. what the independent and dependent value and produce a table of the results

.Viable Plate Count Using The Formula: Cfu/ml = (no. Of Colonies X Dilution Factor)

.Viable plate count Using the formula: cfu/ml = (no. of colonies x dilution factor) / volume of culture plate In plate 10-4 there were 150 colonies counted. Experimental process: Pipet 0.25 mL of the S. cerevisiae solution into the test tube labeled 10-1. Pipet the solution up and down several times to ensure all organisms are rinsed from the pipet into the test tube. Pipet 0.25 mL of the 10-1 S. cerevisiae solution into the test tube labeled 10-2. Pipet the solution up and down several times to ensure all organisms are rinsed from the pipet into the test tube. Repeat the transfer process to pipet the S. cerevisiae solution from the 10-2 tube to the 10-3 tube; from the 10-3 tube to the 10-4 tube; from the 10-4 tube to the 10-5 tube; and from the 10-5 tube to the 10-6 tube. The yeast was added to 2.25ml of distilled water. The a pipet 0.125 mL (4 drops) of each solution was added to the corresponding plate. Calculate: – Dilution Plate CFUs – Dilution Factor of Viable Plate – Volume of Diluent added to Plate – CFU/mL of Original Sample: – CFU/(Volume x Dilution Factor)

Use The Henderson-Hasselbach Equation To Answer The Following. The PKa Of The -SH Group

Use the Henderson-Hasselbach equation to answer the following. The pKa of the -SH group of free cysteine is 8.5. The cytosol of human cells is normally pH 7.3. What would be the % ionisation of the -SH group of free cysteine in the cytosol?

22.) (2 Pts) Glycophorin A Is A 131 Residue Integral Membrane Protein Than Contains

need help with 23. i believe 22’s answer is 20 residues (need question 22 to answer question 23).

Sponges And Ctenophores Have Both Been Proposed As Basal Metazoans. Imagine That You Wanted

Sponges and ctenophores have both been proposed as basal metazoans. Imagine that you wanted to provide additional evidence to help resolve this question. Which of the following projects would be the best next step? A) more extensive study of DNA sequences in the bilateria B) ultrastructural (that is, electron microscope) comparisons of choanoflagellates and sperm cells from arthropods C) measurements of molecular clocks from the Lophotrochozoa D) more extensive studies of DNA sequences in both groups Answer: B please explain the reason

Animal Cells Go Through The Same 4 Stages Of Mitosis As Plant Cells. However,

Animal cells go through the same 4 stages of mitosis as plant cells. However, unlike plant cells, all cells in animals undergo mitosis eventually. In many areas of the body, mitosis is a continuous process, with some areas more active than others. For example, bone marrow continuously produces new red blood cells at a rapid rate (2 x 106 cells/second) because the cells only last 120 days. Examine the photographs and answer the following questions. (1) Chromosomes are normally depicted as they appear in mitosis with two identical sister chromatids joined at the centromere. How is this structure different from the chromosomes in interphase (G1, S and G2)? (2) Are the sister chromatids identical or different? What is the implication of this? (3) How much DNA is present in G1 versus G2? How does this compare to the amount of DNA in gametes?

One Of The Latest Advances In Biotechnology Is The Development Of A Consistently Reproducible

One of the latest advances in biotechnology is the development of a consistently reproducible gene-targeting system called CRISPR-Cas9. It uses an endonuclease attached to a guide RNA to target the specific genomic region to be edited. Discuss the possibilities that this technology presents. What are questions/considerations (scientific OR ethical) that this technology might raise? Please only typed responses, only those with a source will be rated.

Choose One Physical And One Chemical Method. Answer The Following: How Effective Is It

Choose one physical and one chemical method. Answer the following: How effective is it at controlling microbes What is the mechanism of control (how does it do what it does)? If it involves a process, include the process, equipment, recommendations, etc. Please only typed replies, only those with a source will be rated.

By Consuming Fewer Calories We Lengthen People Lives? Answer Yes Or No And

by consuming fewer calories we lengthen people lives? Answer Yes or No and why

During Vigorous Exercise The Lactate Produced In The Muscle Travels To The Liver

During vigorous exercise the lactate produced in the muscle travels to the liver for recycling. Explain why starting with lactate is beneficial for the liver gluconeogenesis pathway. State whether glycogen synthase and glycogen phosphorylase are phosphorylated or dephosphorylated in the glycogen metabolism pathways after the binding of epinephrine to liver or muscle cell receptors and how this affects their activity. Describe two possible metabolic paths glucose-6-phosphate could take if glycolysis is inhibited.

Elizabeth Smith, CMA (AAMA), Just Started Working For Coventry Family Practice. Connie Barnaby,

Elizabeth Smith, CMA (AAMA), just started working for Coventry Family Practice. Connie Barnaby, RMA, is the clinical manager of the office. Connie is helping Elizabeth during the orientation period of her new job. At the start of the day, Connie asks Elizabeth to make sure all examination rooms are stocked with necessary supplies. What supplies would an examination room typically contain? What is the function of the supplies in a typical examination room? How should Elizabeth prepare the examination room for the next patient?

DEMONSTRATION B: Sequential Stages Of Spermatogenesis In The Male Mouse. The Laboratory Mouse, Mus

DEMONSTRATION B: Sequential stages of spermatogenesis in the male mouse. The laboratory mouse, Mus musculus L., has 2n=40 chromosomes: 19 pairs of autosomes plus sexchromosomes, XX in the female and XY in the male. The process of making a gamete in both sexes involves two meiotic cell divisions. Thus, after interphase and DNA synthesis, there are 2 rounds of prophase, metaphase, anaphase and telophase with the production of haploid gametes. In the first round of prophase (prophase I), recombination occurs with at least one chiasma formed for every chromosome. Examine the photographs and answer the following questions. QUESTIONS B1. How many chromosomes are present during late prophase and metaphase of the first division of meiosis in the mouse? [Remember # chromosomes = # centromeres.] B2. How many chromosomes are present during metaphase of the second meiotic divisions? [Remember # chromosomes = # centromeres.] B3. How many chromosomes are present in each gamete following the completion of meiosis? Following meiosis, when would the mouse 2n=40 chromosome number be restored? B4. Some stages of meiosis are either very rapid or require energy. (Note: No energy source is available during slide preparation). Therefore, these stages are missing from the demonstration. Which stages are missing in the photographs here? B5. At what phase(s) of meiosis can chiasmata be observed in the bivalents? (Note: chiasmata are the physical manifestation of crossovers (ie recombination events) and the bivalents are those chromosomes which are paired and undergoing recombination.) B6. What are the 2 most important differences in the products from mitosis vs meiosis in diploids? Why are these differences important?

Mitosis Is The Duplication Of ? Which If The Following Is Not A Unique

mitosis is the duplication of ? which if the following is not a unique feature of meiosis? crossing-over can occur between homologous during? the difference between anaphase 1 and anaphase 2?

Most Multicellular Eukaryotes Form Gametes By? _________ Distinguishes Semiotic Prophesy Fro. Mitotic Prophase. If

most multicellular eukaryotes form gametes by? _________ distinguishes semiotic prophesy fro. mitotic prophase. if a gamete has 4 chromosomes, the so.atuc cells Formed from it have ___________ chromosomes. sex reproduction favors?

A Student Conducts An Enzyme Experiment Revolving Around Changing The Enzyme Concentration, And Its

A student conducts an enzyme experiment revolving around changing the enzyme concentration, and its effects upon the rate of reaction when applied to the protease enzyme pepsin and albumen in the presence of a pH Buffer of 4. The student obtains the following results based upon the time taken for the disappearance of opaqueness (cloudiness) normally associated with a suspension of albumen. The student obtains the following results; it took 2 minutes and 16 seconds for 2.5% to clear the albumen once the pepsin was added, 3 minutes and 12 seconds for the 2%pepsin, whilst the 1.5% pepsin too four minutes and twenty seconds. 0.5% pepsin gave a result of nine minutes and 15 seconds, whilst the 1.0% pepsin took 6 minutes and ten seconds. The student is informed that as the results reflect the sue of substrate and not the production of product, their results must be converted to 1/T (where T = time in seconds) for the rate of reaction and their calculations shown. Variable : Independent variable Dependent variable

What Would You Do If The Patient Presents Diaphoresis In The Axillary Area?

What would you do if the patient presents diaphoresis in the axillary area?

At High Levels Of Exercise, An Increase In The Respiratory Exchange Ratio (sometimes To

At high levels of exercise, an increase in the respiratory exchange ratio (sometimes to over 1.0) is frequently seen.  What fuel would you be solely burning to have this data (Carbohydrate, fats, protein)?  Why do you think this would be the best fuel of choice with high power output?  

1. Malaria Is Mostly Confined To A Region Around The Equator Known As The

1. Malaria is mostly confined to a region around the equator known as the malaria belt because mosquitoes are widespread in regions near the equator. days are longer near the equator, giving the mosquitoes more time to feed (and spread the malarial parasite). malaria is spread only during the winter and mosquitoes cannot survive cold temperatures, therefore they are restricted to areas near the equator. people living outside the malaria belt have generally been vaccinated against the disease. 2. Please choose the correct explanation regarding these tapeworm dimensions—30 feet long, yet extremely thin. (more than 1 answer) A. The thinness of the worms allows maximal absorption of nutrients. B. Their segments, called proglottids, are produced at the neck, adding length to the worm. C. The male and female worms attach end-to-end during reproduction, making them appear to be longer than they really are. D. They are flattened nematodes. 3. Please choose the explanation for why people who have had malaria cannot donate blood for the rest of their lifetime. The malarial parasite can live in liver cells for dozens of years. Even with quinine drugs, the malarial parasite stays in red blood cells. The blood of a malarial patient will have antibodies in it, and this can produce malaria in the recipient. The blood of a malarial patient has less hemoglobin. 4. The thick protective cyst of the Giardia flagellate is instrumental in the ability of the cell to (more than one answer) survive for several weeks in the environment. survive the acidic pH of the stomach. survive in chlorinated drinking water. damage the epithelial cells of the jejunum. metabolize carbohydrates in the small intestine.

1)Based On The Curve In The Figure Above, Approximately How Many Seal Pups Would

1)Based on the curve in the figure above, approximately how many seal pups would be predicted for 2004? For 2007? 2)Reports from two more recent grey seal pup surveys estimated forty-one thousand one hundred (41100) pups in 2004 and fifty-four thousand five hundred (54 500) pups in 2007. Are these estimates close (i.e., within ten thousand pups) to the values predicted by the 1962-1997 growth curve shown in Figure 1? Explain what appears to be happening to the pattern of growth in this population, taking into account the more recent data. PLEASE DO NOT ANSWER IF YOU ARE NOT SURE!!

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