Diana is concerned with setting a correct production level. She
Get college assignment help at Smashing Essays Question Diana is concerned with setting a correct production level. She can produce 500 units or 1100 units. Regardless of production, there is a 45% chance of high demand (2000 units) and a 35% chance of low demand (350 units) and a 20% chance of average demand (1000 units). Each unit costs $15 to produce and sells for $25. She can only sell the minimum of either demand or production (since she can’t sell what she doesn’t make and can’t sell what isn’t demanded).Which production decision should Diana make based on expected value of profit?
In the article “Coffee, Caffeine, and Risk of Depression Among
Question In the article “Coffee, Caffeine, and Risk of Depression Among Women” in the September 2011 edition of the Archives of Internal Medicine, researchers investigated the relationship between caffeine consumption and depression among women. Researchers compared two groups of women (among others) in this study: those who do not drink coffee and those who routinely drink 4 or more cups of coffee each day. To determine if the observed difference in the study is statistically significant, we ran a simulation based on the assumption that the proportion who are depressed in the two groups is the same. In the sampling distribution the difference in the sample proportions is the proportion depressed in coffee drinkers minus the proportion depressed in non-coffee drinkers. The results of the simulation and the corresponding normal model are shown below.Which conclusion seems the most reasonable?The sample difference suggests that drinking coffee may be associated with lower rates of depression.The sample difference proves that drinking coffee lowers the rate of depression in women.The sample difference suggests that drinking coffee does not affect depression rat ATTACHMENT PREVIEW Download attachment SD.png About 70 of the 2,000 random samples Area = 0.035 -0.04- -3 F -0.03 -0.02 -0.01 0.0 0.01 0.02 0.03 0.04 -2 – 1 0 2 3 Z-scores -1.81 Difference in sample means from this study
Blood type AB is found in only 3% of the
Question Blood type AB is found in only 3% of the population style=”color:#0000FF;”>†. If 340 people are chosen at random, find the probability of the following. (Use the normal approximation. Round your answers to four decimal places.)(a) 5 or more will have this blood type (b) between 5 and 10 will have this blood type
Week 3 Assignment Submit Assignment style=”color:rgb(45,59,69);”> · Due Monday by
Question Week 3 Assignment Submit Assignment style=”color:rgb(45,59,69);”> · Due Monday by 11:59pm · Points 12 · Submitting a file upload Test Development Proposal: Step TwoThis assignment is the second step toward completing your Final Test Development Proposal in Week 6. Using your construct of interest from Week 1 and building upon the instruments and information you found in Step One (Week 1), literature review on your construct of interest and the 5-7 instruments used to assess it. Thus, the literature review should explain your construct of interest thoroughly, as well as provide thorough reviews of the 5-7 instruments used to measure it. This is slightly different from other literature reviews, whereby the idea is to review and critique the study and findings. For this literature review you are not reviewing the study but rather are reviewing and critiquing the instrument based on what studies and other researchers have found. The idea here is to review the instrument and its usefulness in measuring your construct. Thus, what does the instrument measure, how reliable and valid is it, and what are its strengths and weaknesses? What is lacking in the instrument which paves the way for the necessity of your newly developed instrument? How are these instruments different from what you will develop?
Vertical banded gastroplasty is a surgical procedure that reduces the
Question Vertical banded gastroplasty is a surgical procedure that reduces the volume of the stomach in order to produce weight loss. In a recent study, 82 patients with Type 2 diabetes underwent this procedure, and 59 of them experienced a recovery from diabetes. Does this study provide convincing evidence that more than 60% of those with diabetes who undergo this surgery will recover from diabetes? Use the α = 0.05 level of significance.
Tell me two ways in which statistics is relevant to
Question Tell me two ways in which statistics is relevant to your “everyday” life. How does it affect you personally? No online material – just give me your opinion
Subject: Statisticscan you help me with assignment of statistics
Question Subject: Statisticscan you help me with assignment of statistics
I need help with this question, I don’t understand what
Question I need help with this question, I don’t understand what the question means when it is mentioning the 95% confidence interval. How would I factor the confidence interval in these questions? ATTACHMENT PREVIEW Download attachment Screen Shot 2019-07-01 at 6.49.22 PM.png C) From Health Canada, the latest statistics on COPD rates show that for 2013, the annual national rate is 4% and that the provinces with the lowest rates are Manitoba and Saskatchewan at 2.8% and 2.9%, respectively. Statistica Canada. 2014. Heath Trends. Statistics Canada Catalogis No. 62-213-XWE. Ottawa. Rainand June 12, 2014. help:www 12 staleange. cartwah-santa $2-213/index.cimYLang-ENG a) Here in Ontario, our Minister of Health wants an updated estimate for the province. We know that the Ontario estimate will be very close to the national number so using this figure, and using the 95% confidence for our estimate and a reasonable acceptable error of 0.5%, how many people must be surveyed? (4) b) Now using the results of (a), a survey was conducted and it was found that 206 people in the sample had COPD. From this result, test the claim at 95% confidence that the result from Ontario was different from that of the national average. 1. State the Null and Alternative Hypothesis (1) Prepare the PDF and state the Decision Rule (1,1) ill. Compute the test statistic (2) W. What is the decision (1) V. What is your interpretation? (1) vi. What is the P-value? (2) c) From the sample information of part (b). determine the 95% confidence interval. Does this support your decision/conclusion from part (b)? Explain. (2,1) d) Is it possible to state that the current rate for Ontario is even smaller than the posted rates for Manitoba and Saskatchewan in 2013? That is, Ontario had the lowest COPD rate in the country. Explain (1,1)
This question was created from stat503_fall2018_hw5sol.docx https://www.coursehero.com/file/37470885/stat503-fall2018-hw5soldocx/ Can you explain
Question This question was created from stat503_fall2018_hw5sol.docx https://www..com/file/37470885/stat503-fall2018-hw5soldocx/ Can you explain how they got this value? ATTACHMENT PREVIEW Download attachment 37470885-323663.jpeg 4. [2 points] You randomlyr sample a single male from the population. How many songs is he expected to have in his repertoire? 13 EIIYiI=Z yp(y):3.474 J’=5 A randomly selected male is expected to have 8.474 songs in his repertoire, on average.
Part I: Coin-Toss Experiment 1. Toss three coins (at once)
Question Part I: Coin-Toss Experiment 1. Toss three coins (at once) 50 times and record the outcomes in terms of the number of heads. Use the table below to organize your data. You can manually toss three coins or use an online simulator of your choice. Based on your data, determine the empirical probability of the following events: i. P(no heads) ii. P(one head) iii. P(two heads) iv. P(three heads) b. Write out the sample space for tossing three coins. c. Determine the theoretical probability of the following events: i. P(no heads) ii. P(one head) iii. P(two heads) iv. P(three heads) d. Do the empirical results agree with the theoretical results? How could you get the empirical results to be closer to the theoretical results?
I quite don’t understand how to do this for sure.A.
Get college assignment help at Smashing Essays Question I quite don’t understand how to do this for sure.A. Create a set of 5 points that are very close together and record the standard deviation. Next, add a sixth point that is far away from the original 5 and record the new standard deviation.What is the impact of the new point on the standard deviation? Do not just give a numerical value for the change. Explain in sentence form what happened to the standard deviation.B. Create a data set with 8 points in it that has a mean of approximately 10 and a standard deviation of approximately 1. Use the second chart to create a second data set with 8 points that has a mean of approximately 10 and a standard deviation of approximately 4. What did you do differently to create the data set with the larger standard deviation? Go back to the spreadsheet and clear the data values from Question 1 from the data column and then put values matching the following data set into the data column for the first graph.50, 50, 50, 50, 50.Notice that the standard deviation is 0. Explain why the standard deviation for this one is zero. Do not show the calculation. Explain in words why the standard deviation is zero when all of the points are the same. If you don’t know why, try doing the calculation by hand to see what is happening. If that does not make it clear, try doing a little research on standard deviation and see what it is measuring and then look again at the data set for this question. Go back to the spreadsheet one last time and put each of the following three data sets into one of the graphs. Record what the standard deviation is for each data set and answer the questions below. Data set 1: 0, 0, 0, 100, 100, 100 Data set 2: 0, 20, 40, 60, 80, 100 Data set 3: 0, 40, 45, 55, 60, 100 Note that all three data sets have a median of 50. Notice how spread out the points are in each data set and compare this to the standard deviations for the data sets. Describe the relationship you see between the amount of spread and the size of the standard deviation and explain why this connection exists. Do not give your calculations in your answer—explain in sentence form. For the last 2 questions, use the Project 1 Data Set.4. Explain what an outlier is. Then, if there are any outliers in the Project 1 Data Set, what are they? If there are no outliers, say no outliers.5. Which 4 states have temperatures that look to be the most questionable or the most unrealistic to you? Explain why you selected these 4 states. For each state, give both the name and the temperature. Data Data x x 1 1 5 1 2 1 10 1 3 1 SD 1.58 15 1 SD 12.25 4 1 Mean 3.00 20 1 Mean 22.50 5 1 Median 3.00 25 1 Median 22.50 1 30 1 1 35 1 1 40 1 1 1 Data x 2 1 2 1 2 1 SD 1.07 2 1 Mean 3.00 4 1 Median 3.00 4 1 4 1 4 1 1 As you enter your numbers into one of the data columns, the chart next to it will automatically adjust the x-axis scale to match the values that have been entered. SD = Standard Deviation ATTACHMENT PREVIEW Download attachment s.jpg Data Data X 5 10 2 1.58 15 SD 12.25 3 SD Mear 22.50 4 Mear 3.00 20 5 Median 3.00 25 Median 22.50 30 35 5 6 0 10 20 30 40 50 1 2 3 4 40 Data X 2 IN 2 SD 1.07 2 Mean 3.00 4 Median 3.00 4 4 1 2 3 4 As you enter your numbers into one of the data columns, the chart next to it will automatically adjust the x-axis scale to match the values that have been entered. SD = Standard DeviationRead more
I really don’t know how to answer this one.Please help
Question I really don’t know how to answer this one.Please help me. style=”color:#000000;”>Visit the NASDAQ historical prices weblink. First, set the date range to be for exactly 1 year ending on the Monday that this course started. For example, if the current term started on April 1, 2018, then use April 1, 2017 – March 31, 2018. (Do NOT use these dates. Use the dates that match up with the current term.) Do this by clicking on the blue dates after “Time Period”. Next, click the “Apply” button. Next, click the link on the right side of the page that says “Download Data” to save the file to your computer. This project will only use the Close values. Assume that the closing prices of the stock form a normally distributed data set. This means that you need to use Excel to find the mean and standard deviation. Then, use those numbers and the methods you learned in sections 6.1-6.3 of the course textbook for normal distributions to answer the questions. Do NOT count the number of data points. Complete this portion of the assignment within a single Excel file. Show your work or explain how you obtained each of your answers. Answers with no work and no explanation will receive no credit. 1. a) Submit a copy of your dataset along with a file that contains your answers to all of the following questions.b) What the mean and Standard Deviation (SD) of the Close column in your data set?c) If a person bought 1 share of Google stock within the last year, what is the probability that the stock on that day closed at less than the mean for that year? Hint: You do not want to calculate the mean to answer this one. The probability would be the same for any normal distribution. 2. If a person bought 1 share of Google stock within the last year, what is the probability that the stock on that day closed at more than $1150? 3. If a person bought 1 share of Google stock within the last year, what is the probability that the stock on that day closed within $50 of the mean for that year? (Hint: this means the probability of being between 50 below and 50 above the mean) 4. If a person bought 1 share of Google stock within the last year, what is the probability that the stock on that day closed at less than $900 per share. Would this be considered unusal? Use the definition of unusual from the course textbook that is measured as a number of standard deviations5. At what prices would Google have to close in order for it to be considered statistically unusual? You will have a low and high value. Use the definition of unusual from the course textbook that is measured as a number of standard deviations.6. What are Quartile 1, Quartile 2, and Quartile 3 in this data set? Use Excel to find these values. This is the only question that you must answer without using anything about the normal distribution. 7. Is the normality assumption that was made at the beginning valid? Why or why not? Hint: Does this distribution have the properties of a normal distribution as described in the course textbook? Real data sets are never perfect, however, it should be close. One option would be to construct a histogram like you did in Project 1 to see if it has the right shape. Something in the range of 10 to 12 classes is a good number.
I really don’t understand how to solve this problem or
Question I really don’t understand how to solve this problem or answer to those problem. style=”color:#000000;”>When performing a hypothesis test, you must make an assumption in order to perform it. Assume that the hypothesis you are testing (the null hypothesis) is true. This assumption allows you to calculate the probability of the test results. You then use that probability to decide whether or not to accept the hypothesis and the claim associated with it. The more likely the results, the more readily you accept the hypothesis. This kind of analysis can be used to evaluate any idea for which there are enough facts or data. For example, what about the premise that Jesus is the Son of God? Josh McDowell takes a similar approach to answering this question in his book, Evidence That Demands a Verdict (Campus Crusade for Christ, 1972). In his book, McDowell collects a variety of information that attests to the Bible’s validity and Jesus’ claims to being the Son of God. He includes the interesting results of a large volume of research. In the section about messianic prophecy, he quotes the probabilistic analysis of Peter Stoner in Science Speaks (Moody Press, 1963). Stoner used the assumption that Jesus was just a man and not the Son of God to perform a probability analysis and hypothesis test on some messianic prophecies. In this case the hypothesis was that Jesus was not the foretold Messiah or the Son of God. He then examined the probability of a selection of prophecies coming true if Jesus was in fact not divine. Using a selection of 8 prophecies, Stoner estimated that the probability of all 8 prophecies being fulfilled is 1 in 1017. Using the language of hypothesis tests, this means that you would reject the hypothesis that Jesus is not the Messiah for any α > 10-17. To put it another way, α > 0.00000000000000001. The smallest α that is normally used for a hypothesis test is α = 0.01. This means that you can safely reject the hypothesis that Jesus is not the Messiah or the Son of God. For more on this, see Josh McDowell’s book Evidence That Demands a Verdict. Peter Stoner’s work can be found in Science Speaks, published by Moody press. Stoner’s book has recently been rereleased in e-book format. You can find it in the Module/Week 7 Additional Materials folder. The references for the 8 Old Testament prophecies that Peter Stoner analyzed are listed below along with the verse references for their fulfillment. It is likely that most students in this course believe that Jesus Christ is divine, so listing probabilities of Him doing certain things is irrelevant. However, Stoner says to the skeptical, “Okay, let’s have it your way for a second. If Jesus of Nazareth was just an ordinary man, what is the probability that he could fulfill all the prophecies by chance?” Old Testament Prophecies New Testament FulfillmentMicah 5:2 Matthew 2:4-6Malachi 3:1 Mark 1:2-8Zechariah 9:9 Matthew 21:4-11Psalms 41:9 Luke 22:21Zechariah 11:12 Matthew 26:15Zechariah 11:13 Matthew 27:3-10Isaiah 53:7 Mark 14: 60-61Psalms 22:16 John 19:17-18 In Discussion Board Forum 2, post a thread that includes the following:1. Type out each Old Testament prophecy with the verse reference followed by the New Testament verse with the fulfillment. 2. Which one of the 8 prophecies and its fulfillment spoke to you the most? Write at least 150 words about this verse and your thoughts about it.3. These prophecies and their fulfillment are definitely evidence that Jesus is the Messiah. People have different opinions about whether or not there is absolute proof of this. Do you think these verses prove that Jesus is the Messiah? Write at least 250 words about your opinion on this. Be sure to explain the reasons behind your thinking. Whether you believe that Jesus is the Messiah or not, please give your honest opinion. Any honest, thoughtful opinion will receive full credit. please help me how to finish this work
Stat 333 – Assignment 2 Question 1 ATTACHMENT PREVIEW Download
Question Stat 333 – Assignment 2 Question 1 ATTACHMENT PREVIEW Download attachment Screen Shot 2019-07-01 at 7.34.49 PM.png 1. Suppose we continue to randomly select letters with replacement from the set {A, B, C, D}. Let T = be the number of letters we need to collect in order to have both letter A and letter B at least once. For example, suppose we have a sequence of letters CCADABB . … Then T =6 in the above sequence. (a) Find the probability generating function of T and use it to find P(T = n) for n 2 1. (b) Use the probability generating function of T to find E(T) and Var(T). Hint: T can be expressed as the summation of two independent rvs.
/>The mean and standard deviations are derived from the content
Question />The mean and standard deviations are derived from the content of the article in the hyperlink. Then divide your answer as follows and complete the relevant calculations: Pre-treatment Post-treatment x̅ s x̅ s BMI FSH mean hirsutism these are ± values i. BMI a. The 95% and 99% confidence intervals (3 marks). b. The null and alternative hypothesis that the after treatment results are significantly different from the before treatment results. ATTACHMENT PREVIEW Download attachment 65927798_343579192963691_5340115349457076224_n.jpg format: ons, pre and post treatment for each of BMI, FSH and mean hirsutism. I recommend the following Pre-treatment Post-treatment X S X S BMI 25.S / 4.4 23.6 / 3.7 P = 00. 47 FSH 5.7 / 2.6 4.5 2.7 these are values P = 0. 083 mean hirsutism 13. 8 / 4.2 9.2 2.42 P = 20.601 e mean and standard deviations are derived from the content of the article in the hyperlink. Then divide your answer follows and complete the relevant calculations:
This question is related to a theory of sampling survey’s
Question This question is related to a theory of sampling survey’s class ATTACHMENT PREVIEW Download attachment Number1.PNG
Which of the following matrices are in row-reduced form?(Note: The
Question Which of the following matrices are in row-reduced form?(Note: The dotted vertical line in each matrix should be a single vertical line.)I. 1 0 | -6 0 1 | 2II. 0 1 | -6 1 0 | 2III. 1 0 -6 | 2 0 1 0 | 4a) None of themb) II and III onlyc) All of themd) I and II onlye) I and III only
This is related to a sampling course ATTACHMENT PREVIEW Download
Question This is related to a sampling course ATTACHMENT PREVIEW Download attachment Number5.PNG
Suppose you randomly sample 9 male sparrows from this population.
Question Suppose you randomly sample 9 male sparrows from this population. What is the probability that exactly 2 of them have at least 11 songs in their repertoires? To find this probability, you can define as a “success;” then find the probability of success for a given bird, and apply the binomial distribution. Please show your work.Table 1: Repertoire sizes of male song sparrows in Hort Park. Number of songs Proportion of males4 0.0285 0.1326 0.2027 0.2098 0.1399 0.12310 0.09711 0.02812 0.042Total 1.000
The coefficient of variation (CV) for a variable is calculated
Question The coefficient of variation (CV) for a variable is calculated as CV=sd/mean×100%Suppose another population of song sparrows is found to have a coefficient of variation for repertoire size of 27%. Is the Hort Park population more or less variable than this other population? Please show all of the steps in your calculations. Note that CV is usually calculated with the sample mean and sample standard deviation. Here, you know the population distribution for Hort Park, so you can use those values instead. Table 1: Repertoire sizes of male song sparrows in Hort Park. Number of songs Proportion of males4 0.0285 0.1326 0.2027 0.2098 0.1399 0.12310 0.09711 0.02812 0.042Total 1.000
Recent studies have shown that out of 1,000 children, 885
Question Recent studies have shown that out of 1,000 children, 885 children like ice cream. What is the 99% confidence interval for the true proportion of children who like ice cream, based on this sample? Round z⋆ to two decimal places and other answers to four decimal places.
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