[H+22++Rearranging in terms of pCO2pCO23+          = 10-5.603×3-1.47-6.33-5.61-10.33

] =K1KHpCO/[H] x ([H] + 2K2)

gives:

= [H+]/(K1KH([H] + 2K2))

/(1010(10 +2×10)

= 396 ppmv (parts per million by volume)

Suppose we raised atmosperic CO₂ to 732 ppmv, what would the resulting pH be? Solve for your answer. Did pH increase or decrease.

NOTE: When answering you’ll get a cubic relating H⁺ to pCO₂ you’ll need to examine the magnitude of different terms to decide on how to simplify to get your answer.

I need assistance in algebraically answering how to assess the cubic relationship by showing a breakdown of steps

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