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In a random sample of 40 ​refrigerators

/in /by

In a random sample of 40 ​refrigerators, the mean repair cost was ​$112.00 and the

population standard deviation is ​$15.30. Construct a 90%

confidence interval for the population mean repair cost. Interpret the results.Construct a 90​% confidence interval for the population mean repair cost.

A. With 90​% confidence, it can be said that the confidence interval contains the true mean repair cost.

B. With 90% confidence, it can be said that the confidence interval contains the sample mean repair cost.

C. The confidence interval contains 90% of the mean repair costs.

 
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