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velocity

Question

A model rocket is launched with an initial velocity of 250 style=”color:rgb(0,0,0);”> ft per second. The height h, in feet, of the rocket t seconds after the launch is given by h = −16t2 + 250t. How many seconds after the launch will the rocket be 600 ft above the ground? Round to the nearest hundredth of a second. (Enter your answers as a comma-separated list.)

 
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