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X_L=2πʄL=2π(12kHz)(100mH)=7.54KΩ

show work and phasor diagram) I need help making the diagram I did the

problem.

X_L=2πʄL=2π(12kHz)(100mH)=7.54KΩ

                X_C=1/2πʄC=1/2π(12kHz)(10nF) =1.33KΩ

                X_S=X_L-X_C=7.54kΩ-1.33kΩ=6.21kΩ

                Z_T=√(X_S^2+R^2 )=√(〖6.21kΩ〗^2+〖910Ω〗^2 )=6.28kΩ

                I=VS/ZT=8V/6.28kΩ=1.27mA

                V_L=I*X_L=(1.27mA)(7.54kΩ)=9.6V∠90°

                V_C=I*X_C=(1.27mA)(1.33kΩ)=1.7V∠-90°

                V_R=I*R=(1.27mA)(910Ω)=1.2V∠0°

                V_LC=V_L-V_C=9.6V-1.7V=7.9V

                θ=tan^(-1)⁡〖(VLC/VR〗)=tan^(-1)⁡〖(7.9V/1.2mV〗)=89.9°

 
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