A closed square pyramid tank (base width: 6.0 m; height 3.0m) sitting on its square base, has a 1.0m depth of water. Suppose this tank is inverted (turned upside down) and is made to stand on it's apex. Calculate the new depth of water in this pyramid-shaped tank. Report your answer in meters, using two sig figs. I calculated the volume of the whole pyramid and the pyramid with 1 m of water in it but I don't understand how I am supposed to calculate the new volume of the pyramid?