I do not understand how to determine if the data indicates that at
least two of the mean percent differences between the three groups are different if its being tested at a 10% level?
Background:This group measured the calories in food and then found the percentage difference between what was measured and what was on the label. The foods were ones that are nationally advertised, regionally distributed, or locally prepared. The data is in table #1 below.
Percent Differences Between Measured and Labeled Food
National Advertised————–Regionally Distributed————–Locally Prepared
2—————————————–41—————————————-15
-28————————————–46—————————————-60
-6—————————————-2—————————————–250
8—————————————–25—————————————145
6—————————————–39—————————————-6
-1—————————————16.5————————————–80
10—————————————17—————————————-95
13—————————————28—————————————-3
15————————————–( -3)
-4————————————–14
-4————————————–34
-18————————————-42
10
5
3
-7
3
-0.5
-10
6

 

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THE MARGIN OF ERROR (BOUNDARY) FOR A PROPORTION: EBP = z * √ [(p’*q’)
/ n ]. IF WE KNOW THE EBP, AND THE PROBABILITIES OF EVENTS p’ AND q’ OCCURRING, WE CAN DETERMINE THE NECESSARY SAMPLE SIZE. LET’S SAY THAT THE EBP = 7% AND THAT p’ = 40% AND q’ = 60% (REMEMBER THAT p’ AND q’ MUST ADD UP TO 1.00 OR 100%)

CALCULATE THE NECESSARY SAMPLE SIZE (n) USING THESE NUMBERS. (HINT: CAN’T USE %’s, NEED TO CONVERT THEM TO DECIMAL FRACTIONS) ALSO, WHEN NO ALPHA VALUE IS GIVEN AS HERE, ASSUME α =5%

 (BUT, DO WE USE α/2 HERE SINCE IT’S A CI?)

There is no other information to give on the assignment. The following is as far as I was able to get alone:

.07 = z * √ [(.4’*.6′) / n ].

 

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