ChE 317 Fall 2017 Homework 2 Due Sept 6 th Problem 1: A stream consist of: H20 0.4 C2H5 OH 0.3 CH3OH 0.1 CH3COOH 0.2 All in weight fractions is fed to distillation column at the rate of 1000 lbm/h. Convert these stream variables to: a) Molar species flow rates.
ChE 317 Fall 2017 Homework 2 Due Sept 6 th Problem 1: A stream consist of: H20 0.4 C2H5 OH 0.3 CH3OH 0.1 CH3COOH 0.2 All in weight fractions is fed to distillation column at the rate of 1000 lbm/h. Convert these stream variables to: a) Molar species flow rates. b) Total molar flow and mole fractions. c) Mole fractions, water-free basis. Problem 2: A process for producing methane from synthesis gas and steam is fed 6 kgmol/min of a gas consisting of 50% H2, 33 1/3 % CO, and the rest CH4 (all on a mole basis) as well as 72 kg/min of steam (H2O). The products are 3 kgmol/min of liquid water and 96 kg/min of a gas consisting of 25% CH4, 25% CO2, and the rest H2 (all on a mole basis). Determine to three significant figures whether: a) Total mass is conserved. b) Total moles are conserved. c) The moles of each type of atom are conserved. d) The mass of each type of chemical species is conserved. e) What do you conclude is happening in this process? Problem 3: (Mole fraction specification) A 100 kmol/h mixture of four components is to be separated into an overhead and bottom product. The feed composition to the column is as follows: Component, i Mole fraction (zi) 1 0.1 2 0.2 3 0.3 4 0.4 Calculate the product rates and composition for the following sets of specifications: a) Given y1 = 0.21; y2 = 0.35; y3 = 0.2; and D/F =0.4 b) Given y1 = 0.23; y2 = 0.34; x3 = 0.38; and x4 = 0.46 c) Given y1 = 0.2; y2 = 0.3; x2 = 0.15; and x3 = 0.42 Problem 4: (Component rates and Recovery Specifications) Consider the separation of mixture given in problem 3, into distillate and bottoms products to meet the following sets of specifications: Recovery of component j in stream D (rj D ) ππ π· = πππππ (ππ πππ π ) ππ πππππππππ‘ π ππ π π‘ππππ π· πππππ (ππ πππ π )ππ π ππ π‘βπ ππππ a) Distillate flowrate of component 1, D1 = 8.5 kmol/h; bottoms flowrate of component 3, B3 = 23.0 kmol/h; recovery of component 2 in the distillate r2 D = 0.72; recovery of component 4 in the bottoms product r4 B = 0.26 b) Recovery of components 1,2,3 and 4 in the distillate r1 D = 0.82, r2 D = 0.73, r3 D = 0.21, and r4 D = 0.26 Calculate product rates and compositions for each case.