Given four numbers such that the sum of the first, second, third exceeds the fourth by 6, the sum of the squares of the third and fourth exceeds the sum of the squares of first and second by 36, the sum of the product of first and second to the product of third and fourth is 42, and the cube of the fourth equals the sum of the cubes of the other numbers. Determine the average of the four numbers?
Given four numbers such that the sum of the first, second, third exceeds the fourth by 6, the sum of the squares
of the third and fourth exceeds the sum of the squares of first and second by 36, the sum of the product of first and second to the product of third and fourth is 42, and the cube of the fourth equals the sum of the cubes of the other numbers. Determine the average of the four numbers?
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