Given the following timed data, convert mL 0.04 M NaOH to concentration of HCl, [HCl]ttttttt100t0t , in 10 mL aliquots of the reaction of -butyl chloride in isopropanol/water.
Given the following timed data, convert mL 0.04 M NaOH to concentration of HCl, [HCl]ttttttt100t0t
, in 10 mL aliquots of the reaction of -butyl chloride in isopropanol/water. Then convert [HCl] to concentration of -butyl chloride, [RX]. Using a program such as Microsoft Excel, plot (Scatter Chart) time versus natural log of concentration of -butyl chloride at time zero over concentration of -butyl chloride at each time, ln([RX]0/[RX]t). Determine the slope of your plot as instructed in this video. The slope is the rate constant of first order kinetics as given by equation 20.2 of your text. This is equivalent to Figure 20.1 of your text but we don’t have to use the factor 2.303, ln(10), because we are using natural versus base 10 logs. Before the advent of calculators, people actually used tables to look up log values! Hint: [RX] = ? so that [RX] = [RX] – [HCl] which is the equation at the bottom of page 322 of your text?
runtime (min)mL 0.04 M NaOH[HCl]t[RX]tln([RX]0/[RX]t)111422283351244616579216104207 infinity 27
Give only 2 significant digits
Looking for a Similar Assignment? Order now and Get 10% Discount! Use Coupon Code "Newclient"
