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If you know the sample mean for worker satisfaction is 77.3

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If you know the sample mean for worker satisfaction is 77.3, and the
estimated standard error of the mean is 11.7, and the sample size is 30, calculate the 95% confidence interval for a non-directional test (show all your work):

What is the Confidence interval (lower and upper limits)?

What would the written statement be?

 
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