Part1) Consider the cell Ag(s) | Ag+(aq, 0.00021 mol/L) || Pb2+(aq, 0.1 mol/L) | Pb(s) What maximum work can this cell perform (per mole of Pb)? Answer in units of kJ. Part 2) What is the value of ∆Sr? ∆Hf,pb2+ is −1.7 kJ/mol and ∆Hf,ag+ is 105.58 kJ/mol. Answer in J/Mol*K
Part1) Consider the cellAg(s) | Ag+(aq, 0.00021 mol/L) ||Pb2+(aq, 0.1
mol/L) | Pb(s)
What maximum work can this cell perform
(per mole of Pb)?
Answer in units of kJ.
Part 2) What is the value of ∆Sr? ∆Hf,pb2+ is −1.7 kJ/mol and ∆Hf,ag+ is 105.58 kJ/mol.
Answer in J/Mol*K