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Procedure:2323 12solar mass units Y

/in /by

Procedure:2323 12solar mass units
You have learned that Kepler’s third law, P= a, applies to any object orbiting the Sun. Newton was able to derive Kepler’s third law using his law of gravity. Newton’s version includes the mass of both objects, P= a/ (M+ M), and can be used for any object that orbits any astronomical body. In this formula the masses are measured in special units called . The mass of the Sun is equal to one solar mass unit.

If the mass of the second object is very small compared to the first mass, then to a good approximation P2= a3 / M1. Solving for the mass we get M1= a3/ P2. Use this mass formula to determine the mass of Jupiter using data from its moon Sinope: period of orbit is 2.075 years, average orbital distance is 0.158 astronomical units.

Your calculated mass of Jupiter is _________________ solar mass units.

You can convert your result above into kilograms by multiplying it by the mass of the Sun in kilograms, 2.00 x 10 30kg.

Your calculated mass of Jupiter is ____ kg.

Compare your calculated mass of Jupiter (kg) to the actual value.

Percent Difference = 100 x ( your calculated value – actual value ) / ( actual value )

Your calculated Percent Difference is _____ %.

How close did you get? Explain any possible difference.

 
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