The reaction of hydrogen bromide with oxygen proceeds as follows

The reaction of hydrogen bromide with oxygen proceeds as follows:4 HBr(g) + O2(g) → 2 H2O(g) + 2 Br2(g)
A possible mechanism for the reaction is:

step 1 HBr(g) + O2(g) → HOOBr(g)

step 2 HOOBr(g) + HBr(g) → 2HOBr(g)

step 3 HOBr(g) + HBr(g) → H2O(g) + Br2(g)

If the experimentally observed rate law is rate = k[HBr]2[O2], then

a) What is the rate determining step?

b) What is the overall reaction order?

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