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Water initially at 190° F. is left in a room of temperature 70° F to cool.After t T Tte t

/in /by

Water initially at 190° F. is left in a room of temperature 70° F to cool.After t T Tte t
minutes, the temperature of the water is given by () = 70 + 120- 0.096

Find the temperature of the water 20 minutes after it is left to cool. (Round to the nearest degree.)

 
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