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What is the equilibrium constant when 0.125 mol

/in /by

What is the equilibrium constant when 0.125 mol HF is dissolved in
water. Temp = 292 K, and volume of 1.0 L, 7.23% of the HF dissociates to form F -(aq).
HF(aq) + H2O(l) ⇌ F -(aq) + H3O+(aq)

 
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