What is the estimated 95% confidence interval (CI) of the difference

in proportions between schoolchildren and adults developing nausea and vomiting following holiday parties? Assign groups 1 and 2 to be schoolchildren and adults, respectively.
Please note the following: 1) in practice, you as the analyst decide how to assign groups 1 and 2 and subsequently interpret the results appropriately in the context of the data, though for the purposes of this exercise the groups are assigned for you; 2) 0 and 1 are defined as no and yes, respectively, which is a typical coding scheme in Public Health; 3) you might calculate a CI that is different from any of the multiple choice options listed below due to rounding differences, therefore select the closest match; and 4) you may copy and paste the data into Excel to facilitate analysis. Please show your work
Select one:
a. 0.1686 to 0.5927
b. 0.1787 to 0.6579
c. 0.1568 to 0.6638
d. 0.1424 to 0.5364
Table 1. Schoolchildren
Subject
Nausea and
Vomiting?
1
0
2
1
3
1
4
1
5
0
6
0
7
0
8
0
9
1
10
1
11
0
12
1
13
1
14
0
15
1
16
0
17
1
18
0
19
1
20
1
21
1
22
1
23
1
24
0
25
1
26
1
27
0
28
0
29
1
30
0

Table 2. Adults
Subject
Nausea and
Vomiting?
1
0
2
0
3
0
4
1
5
0
6
0
7
0
8
0
9
0
10
0
11
0
12
0
13
0
14
1
15
0
16
0
17
0
18
0
19
0
20
0
21
0
22
0
23
0
24
0
25
0
26
0
27
0
28
0
29
1
30
0
31
0
32
0
33
0
34
0
35
1
36
0
37
0
38
1
39
0
40
1
41
1
42
1
43

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