Question

Where does the 18 come from to answer part e of problem?How many moles of oxygen gas are required to

completely react with 14.3 mol of ethane?

How many grams of oxygen gas are required to completely react with 0.88 mol of ethane?

How many moles of carbon dioxide gas are expected to be produced from the complete reaction of 27.7 g ofethane?e. How many grams of ethane are needed to produce 125 g of water?

Explain your answer Pls.

combustion reaction of ethane is 2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

in this reaction 2 mole C2H6 react with 7 mole O2 to form 4 mole CO2 and 6 mole H2O.

oxygen gas are required to completely react with 14.3 mol of ethane= 7*14.3/2=50.05 moles.

 grams of oxygen gas are required to completely react with 0.88 mol of ethane= 7*0.88*30.07/2=92.61 gm

27.7 g ofethane=27.7/30.07=0.921 mole of ethane

moles of carbon dioxide gas are expected = 4*0.921/2=1.84 mole

125 g of water=125/18=6.944 mole

so ethane are needed= 2*6.944*30.07/6=69.6 gms

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