I need help with que 12-16 on the attached document stat 3001
| I need help with que 12-16 on the attached document stat 3001 |
|
Week 4 Project – STAT 3001Student Name:<Type your name here>Date:<Enter the date on which you began working on this assignment.>Instructions:To complete this project, you will need the following materials:STAT DISK User Manual (found in the classroom in Doc Sharing)Access to the internet to download the Stat Disk program.Part I.Analyze DataInstructionsAnswers1.Open the filePassive andActive Smokeusing menuoptionDatasetsand thenElementary Stats, 11thEdition.This file containssome information on thecontinine levels in smokers,nonsmokers exposed tosmoke (ETS), andnonsmokers not exposed tosmoke (No ETS).How manyobservations are there in thisfile?There are 40 samples with 3 different observations made on eachsample for a total of 120 different observations.2.What would you expect tofind relative to the contininelevel in the groups?The NOETS group lists the cotinine levels for subjects who arenonsmokers and have no exposure toenvironmental tobacco smoke at home or work.The ETS group lists cotinine levels for subjects who arenonsmokers exposed to tobacco smoke athome or work.The SMOKERS group lists cotinine levels for subjects who reporttobacco use.Serum cotinine is a metabolite of nicotine, meaning that cotinine isproduced when nicotine is absorbed bythe body. Higher levels ofcotinine correspond to higher levels of exposure to smoke thatcontains nicotine.Part II. Descriptive Statistics3-6 Generate descriptivestatistics for No ETS,Smokers and ETS groups andVariableSampleMeanSampleStandardDeviationSample Size1
complete the following table.Round mean and standarddeviation to 3 decimal places.No ETS16.3562.53440Smokers172.475119.49840ETS60.575138.084407. Did you get the results youexpected here?Explain why.8. Which of the three groupsexperienced the MOSTvariation? How do youknow?ETS – the variable in stat disk is the highest at 19067.17Part III. Confidence Intervals9. Generate a 90% intervalfor the mean of the No ETSgroup. Paste your resultshere.Margin of error, E = 16.6591890% Confident the population mean is within the range:-0.3091758 < mean <33.0091810. Generate a 90% intervalfor the mean of the Smokergroup. Paste your resultshere.Margin of error, E = 31.8344990% Confident the population mean is within the range:140.6405 < mean <204.309511. Generate a 90% intervalfor the mean of the ETSgroup. Paste your results hereMargin of error, E = 36.7858490% Confident the population mean is within the range:23.78916 < mean <97.3608412. Create a graph below by illustrating all three confidence intervals on one graph using the tools inyour word processor (example below).Stat Disk cannot do this for you. Create your graph and turnthe font red.For this process, I just used the dashes and wrote a scale below the axes.Here is an example, but it is not based on the data you are analyzing:Case 114———————42Case 235————————-70________________________________________0204060Your Solution:13. Based on the confidenceintervals shown above, whatconclusion can you drawabout whether the exposure toYes the exposure to smoke leads to higher continine levels.Due to the fact that ETS range 23.78916 < mean <97.36084and No ETS range -0.3091758 < mean <33.009182
Looking for a Similar Assignment? Order now and Get 10% Discount! Use Coupon Code "Newclient"
