I used the picture attached for my numbers,
I used the picture attached for my numbers, but I can not figure out how to do the Harry Weinberg Equation with this information.
bugs.PNG
Step 1: Determine p and q from the initial population data.
p = number of B alleles / total number of alleles = ____ / ____ =
q = number of b alleles / total number of alleles = ____ / _____ =
2pq = number of heterozygous bugs = ____ /_____ =
Step 2: Predict the future population composition of the initial population. Use the Hardy Weinberg formula p2 + 2pq + q2 = 1 where q2 is the proportion of yellow bugs predicted and [p2 + 2pq] is the proportion of blue bugs predicted. The easiest way to calculate the future probability is to use the formulas below. The number of individuals with the recessive PHENOTYPE (yellow in this case) is predicted using the formula q2, which is the square of the q value calculated in step 1. The decimal value is changed into a % by multiplying by 100 for easy comparison. The number of individuals with the dominant PHENOTYPE (blue in this case) is determined by subtracting the q2 value from 1, then multiply by 100 to obtain the % value. Note that the two percentage predictions (yellow + blue) must add up to 100%.
Predicted proportion of yellow bugs
= q2 = (_______)2
= ________
⇒ ______%
Predicted proportion of blue bugs
= 1 − q2
= [1−_______]
= ______
⇒ ______%
Step 3: Final results of Bug Pop _________ preference data runs.
Observed proportion of blue bugs (ratio) = number of blue bugs / total number of bugs
ratio =_______ / _______
decimal answer =__________
percentage ⇒______%
Observed proportion of yellow bugs = number of yellow bugs / total number of bugs
= _____ / _______
= _________
⇒______%
Step 4: Compare the Hardy-Weinberg predicted and observed final population phenotype percentages
Blue
predicted (From Step 2): _______%
observed (from Step 3 ): _______%
Yellow
predicted (From Step 2): ______ %
observed (from Step 3): _______%